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.NET Framework Class Library

Enumerable.ElementAt<TSource> Method

Returns the element at a specified index in a sequence.

Namespace:  System.Linq
Assembly:  System.Core (in System.Core.dll)
<ExtensionAttribute> _
Public Shared Function ElementAt(Of TSource) ( _
	source As IEnumerable(Of TSource), _
	index As Integer _
) As TSource

Type Parameters

TSource

The type of the elements of source.

Parameters

source
Type: System.Collections.Generic.IEnumerable<TSource>

An IEnumerable<T> to return an element from.

index
Type: System.Int32

The zero-based index of the element to retrieve.

Return Value

Type: TSource
The element at the specified position in the source sequence.

Usage Note

In Visual Basic and C#, you can call this method as an instance method on any object of type IEnumerable<TSource>. When you use instance method syntax to call this method, omit the first parameter. For more information, see Extension Methods (Visual Basic) or Extension Methods (C# Programming Guide).
Exception Condition
ArgumentNullException

source is null.

ArgumentOutOfRangeException

index is less than 0 or greater than or equal to the number of elements in source.

If the type of source implements IList<T>, that implementation is used to obtain the element at the specified index. Otherwise, this method obtains the specified element.

This method throws an exception if index is out of range. To instead return a default value when the specified index is out of range, use the ElementAtOrDefault<TSource> method.

The following code example demonstrates how to use ElementAt<TSource> to return an element at a specific position.

        ' Create an array of strings. 
        Dim names() As String = _
            {"Hartono, Tommy", "Adams, Terry", "Andersen, Henriette Thaulow", "Hedlund, Magnus", "Ito, Shu"}

        Dim random As Random = New Random(DateTime.Now.Millisecond)

        ' Get a string at a random index within the array. 
        Dim name As String = names.ElementAt(random.Next(0, names.Length))

        ' Display the output.
        MsgBox("The name chosen at random is " & name)

        ' This code produces the following output: 
        
        ' The name chosen at random is Ito, Shu

.NET Framework

Supported in: 4.5.2, 4.5.1, 4.5, 4, 3.5

.NET Framework Client Profile

Supported in: 4, 3.5 SP1

Portable Class Library

Supported in: Portable Class Library

.NET for Windows Store apps

Supported in: Windows 8

.NET for Windows Phone apps

Supported in: Windows Phone 8.1, Windows Phone 8, Silverlight 8.1

Windows Phone 8.1, Windows Phone 8, Windows 8.1, Windows Server 2012 R2, Windows 8, Windows Server 2012, Windows 7, Windows Vista SP2, Windows Server 2008 (Server Core Role not supported), Windows Server 2008 R2 (Server Core Role supported with SP1 or later; Itanium not supported)

The .NET Framework does not support all versions of every platform. For a list of the supported versions, see .NET Framework System Requirements.