How to Change the IP Address of an Exchange Virtual Server

 

This topic provides instructions for changing the IP address of an Exchange Virtual Server. This procedure is typically performed when the physical nodes of the cluster are being physically relocated to a different subnet or network.

Before You Begin

The following procedure illustrates this procedure using a two-node cluster that includes Node1 and Node2.

Procedure

To change the IP address of an Exchange Virtual Server

  1. Failover all resources to Node1 and take them offline. To do this:

    1. Log on to Node1 using an account with Administrator privileges.

    2. Open Cluster Administrator.

    3. Move all resource groups to Node1 using the Move Group context menu item for each resource group.

    4. Right click all resource groups and take them offline.

  2. Change the startup type for the Cluster Service to manual. To do this:

    1. Logon to Node1.

    2. Open the Services snap-in.

    3. Double-click the Cluster Service and change the Startup type to Manual.

    4. Repeat steps 2a-2c on Node2.

  3. Power off both nodes, one at a time, and perform the physical relocation.

  4. Change the IP addresses of Node1 and Node2 upon arrival to the new physical location. To do this:

    1. Power on Node1.

    2. Log on to Node1 using an account with Administrator privileges.

    3. Click Start, point to Control Panel, and click Network Connections.

    4. Right-click the local area connection that you want to modify and then click Properties.

    5. Click Internet Protocol (TCP/IP), and then click Properties. The Internet Protocol (TCP/IP) Properties dialog box appears.

    6. Change the IP address accordingly.

    7. Power on Node2 and repeat steps 4b-4f.

  5. Change the cluster IP address. To do this:

    1. On Node1, click Start, and then click Run. In the Open box, type cluadmin /noreconnect and then press ENTER.

    2. When you receive the prompt for the cluster name, enter a period "." (without the quotes), and then click Open.

    3. Take the cluster IP address resource offline.

    4. Change the cluster IP address resource using Cluster Administrator and bring the cluster IP address resource online.

    5. Power on Node2 and test failover the Cluster Group.

Note

If the subnet mask is changed, Public(1) may appear as a network in Cluster Administrator. When both nodes agree on the subnets, the Public network disappears and the Public(1) network is created. You can rename the network Public(1) to Public.

  1. Change the Exchange Virtual Server's IP address. To do this:

    1. Open Cluster Administrator and double-click each IP Address resource (cluster IP address resource and Exchange virtual server IP address resource) to open its properties.

    2. On the Parameters tab of each IP Address resource properties, make sure that the Network to Use box contains Public as the network to use.

    3. Open Exchange System Manager.

    4. Locate the Protocols area under the Exchange Virtual Server that you want to modify. Expand the HTTP, IMAP4, SMTP, and POP3 virtual servers.

    5. Open the properties of each virtual server, and then verify the IP address in the advanced properties at General tab. If necessary, change to the new Exchange virtual server IP address.

    6. Bring the Exchange resources online and verify connectivity to the Exchange virtual server from a client workstation.

  2. Test failover and change the Cluster service startup type to automatic. To do this:

    1. Open Cluster Administrator and failover each resource group a few times.

    2. Open the Services snap-in.

    3. Double-click the Cluster Service and change the Startup type to Automatic.

    4. Repeat steps 7a-7c on Node2.

For More Information

See Also

Other Resources

https://go.microsoft.com/fwlink/?linkid=3052&kbid=230356
https://go.microsoft.com/fwlink/?linkid=3052&kbid=267548
https://go.microsoft.com/fwlink/?linkid=3052&kbid=315691
https://go.microsoft.com/fwlink/?linkid=3052&kbid=241828
https://go.microsoft.com/fwlink/?linkid=3052&kbid=258453