STWithin (geometry Data Type)
Returns 1 if a geometry instance is completely within another geometry instance; otherwise, returns 0.
|Applies to: SQL Server (SQL Server 2008 through current version), Azure SQL Database.|
.STWithin ( other_geometry )
Is another geometry instance to compare against the instance on which
STWithin() is invoked.
SQL Server return type: bit
CLR return type: SqlBoolean
This method always returns null if the spatial reference IDs (SRIDs) of the geometry instances do not match.
The following example uses
STWithin() to test two
geometry instances to see if the first instance is completely within the second instance.
DECLARE @g geometry; DECLARE @h geometry; SET @g = geometry::STGeomFromText('POLYGON((0 0, 2 0, 2 2, 0 2, 0 0))', 0); SET @h = geometry::STGeomFromText('POLYGON((1 1, 3 1, 3 3, 1 3, 1 1))', 0); SELECT @g.STWithin(@h);